I am a new learner in GeNIe. I have been troubled by Bayesian problem.
The problem is stated as follows:
there are three experts to evaluate the security policy of car (s),
A. the first expert (E1) gives three rules:
1) if the security policy of car is "poor", the probability of the accident is 0.4, i.e.,
P(SE11)=0.4.
2) if the security policy of car is "middle", the probability of the accident is 0.2, i.e.,
P(SE12)=0.2.
3) if the security policy of car is "good", the probability of the accident is 0.1, i.e.,
P(SE13)=0.1.
So, we can get the probability of the security policy locted in every rule when the accident existed:
P(E11S=yes)=0.5714, P(E12S=yes)=0.2857, P(E13S=yes)=0.1429.
Correspondingly, the probability of the security policy locted in every rule when the accident not existed:
P(E11S=No)=0.2609, P(E12S=no)=0.3478, P(E13S=no)=0.3913.
B. the second expert (E2) gives three rules:
1) if the security policy of car is "poor", the probability of the accident is 0.5, i.e.,
P(SE21)=0.5.
2) if the security policy of car is "middle", the probability of the accident is 0.2, i.e.,
P(SE22)=0.2.
3) if the security policy of car is "good", the probability of the accident is 0.1, i.e.,
P(SE23)=0.1.
So, we can get the probability of the security policy locted in every rule when the accident existed:
P(E21S=yes)=0.625, P(E22S=yes)=0.25, P(E23S=yes)=0.125.
Correspondingly, the probability of the security policy locted in every rule when the accident not existed:
P(E21S=No)=0.2272, P(E22S=no)=0.3636, P(E23S=no)=0.4092.
C. the third expert (E3) gives three rules:
1) if the security policy of car is "poor", the probability of the accident is 0.4, i.e.,
P(SE31)=0.4.
2) if the security policy of car is "middle", the probability of the accident is 0.2, i.e.,
P(SE32)=0.3.
3) if the security policy of car is "good", the probability of the accident is 0.1, i.e.,
P(SE33)=0.1.
So, we can get the probability of the security policy locted in every rule when the accident existed:
P(E31S=yes)=0.5, P(E32S=yes)=0.375, P(E33S=yes)=0.125.
Correspondingly, the probability of the security policy locted in every rule when the accident not existed: P(E31S=No)=0.2727, P(E32S=no)=0.3182, p
(E33S=no)=0.4091.
Based on above procedures, I donot cumputing the the probability of the accident, i.e., p(S)=? by GeNIe. The attarched file can not get p(S).
Can you help me to build the Beyesian net by using GeNIe at your free.
can you help me to build the Beyesian net by using GeNIe
can you help me to build the Beyesian net by using GeNIe
 Attachments

 Network2.xdsl
 my GeNIe file
 (1.82 KiB) Downloaded 435 times